How many exagallon [U.S.] of kerosene in 1 kilogram calorie? The answer is 2.9436005625879E-23. We assume you are converting between exagallon [U.S.] of kerosene and kilogram calorie. You can view more details on each measurement unit: exagallon [U.S.] of kerosene or kilogram calorie The SI derived unit for energy is the joule. 1 joule is equal to 7.0323488045007E-27 exagallon [U.S.] of kerosene, or 0.00023890295761862 kilogram calorie. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between exagallon [U.S.] of kerosene and kilogram calories. Type in your own numbers in the form to convert the units!
1 exagallon [U.S.] of kerosene to kilogram calorie = 3.3972000573367E+22 kilogram calorie
2 exagallon [U.S.] of kerosene to kilogram calorie = 6.7944001146734E+22 kilogram calorie
3 exagallon [U.S.] of kerosene to kilogram calorie = 1.019160017201E+23 kilogram calorie
4 exagallon [U.S.] of kerosene to kilogram calorie = 1.3588800229347E+23 kilogram calorie
5 exagallon [U.S.] of kerosene to kilogram calorie = 1.6986000286684E+23 kilogram calorie
6 exagallon [U.S.] of kerosene to kilogram calorie = 2.038320034402E+23 kilogram calorie
7 exagallon [U.S.] of kerosene to kilogram calorie = 2.3780400401357E+23 kilogram calorie
8 exagallon [U.S.] of kerosene to kilogram calorie = 2.7177600458694E+23 kilogram calorie
9 exagallon [U.S.] of kerosene to kilogram calorie = 3.057480051603E+23 kilogram calorie
10 exagallon [U.S.] of kerosene to kilogram calorie = 3.3972000573367E+23 kilogram calorie
You can do the reverse unit conversion from kilogram calorie to exagallon [U.S.] of kerosene, or enter any two units below:
The large calorie or kilogram calorie approximates the energy needed to increase the temperature of 1 kg of water by 1 °C. This is about 4.185 kJ, and exactly 1000 small calories.
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